card

if sum of the two cards of the same number is identical with the number in another card,you can remove these three cards.

in otner words,if there are cards as follows:

2 4 7 3 3 6 2 8

as 2 +2=4,three of the  cards can be removed.

finally,two cards of 7,8 remained .therefore ,return 15=7+8.

there is no fixed orders to rermove cards.

 

code:

#include <stdio.h>
#include <stdlib.h>
int test_main(int data[8]);
void build_data(int data[999])
 {
  for(int i=0;i<999;i++)
  {
     data[i]=rand()%24+1;
  }
    }
void main(void)
{ 
 int data[8]={2,4,7,3,3,6,2,8};
 for(int l=0;l<10;l++)
 {
  //build_data(data);
  printf("%d\n",test_main(data));
 }
 return ;
}
 
int test_main(int data[8])
{
   int i,n,sum,p;
   int times[25]={0};
   for(i=0;i<8;i++)//每个数字出现的次数
    {
     times[data[i]]++;
       } 
   for(n=12;n>0;n--)
 {
  while(times[2*n]>=1&&times[n]>=2)
  {
   times[n]=times[n]-2;
   times[2*n]--;
  }
 }
   for(p=1,sum=0;p<=24;p++)
   {
  sum=sum+p*times[p];
   }
   return sum;
}