2020牛客多校第八场 H Hard String Problem(广义后缀自动机)

取最小循环节的最小表示法的字符串,翻若干倍插入广义后缀自动机,最后用树状数组统计parent树上子树包含所有串的节点所代表的字符串的个数,累加即可

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> pii;
const int N = 2e6 + 5;
const int maxn = 300010;
ll ans;
int n;
struct QU { int id,l,r; };
struct Suffix_Automaton
{
    QU qry[N];
    int c[N], ans[N];
    int O, ru[N], link[N], maxlen[N], trans[N][26];
    vector<int>g[N],siz[N];
    int in[N],out[N],tim=0;
    int Q[N],head,tail;
    void add(int p,int v) { for(; p <= O; p += p&(-p)) c[p] += v; }
    int query(int p) { int ret = 0; for(; p; p -= p&(-p)) ret += c[p]; return ret; }
    Suffix_Automaton() { O = 1; }
    int insert(int ch, int last, int id)
    {
        if (trans[last][ch])
        {
            int p = last, x = trans[p][ch];
            if (maxlen[p] + 1 == maxlen[x])
            {
                siz[x].push_back(id);
                return x;
            }
            else
            {
                int y = ++O;
                maxlen[y] = maxlen[p] + 1;
                for (int i = 0; i < 26; ++i)
                    trans[y][i] = trans[x][i];
                while (p && trans[p][ch] == x)
                    trans[p][ch] = y, p = link[p];
                link[y] = link[x], link[x] = y;
                siz[y].push_back(id);
                return y;
            }
        }
        int z = ++O, p = last;
        maxlen[z] = maxlen[last] + 1;
        while (p && !trans[p][ch])
            trans[p][ch] = z, p = link[p];
        if (!p)
            link[z] = 1;
        else
        {
            int x = trans[p][ch];
            if (maxlen[p] + 1 == maxlen[x])
                link[z] = x;
            else
            {
                int y = ++O;
                maxlen[y] = maxlen[p] + 1;
                for (int i = 0; i < 26; ++i)
                    trans[y][i] = trans[x][i];
                while (p && trans[p][ch] == x)
                    trans[p][ch] = y, p = link[p];
                link[y] = link[x], link[z] = link[x] = y;
            }
        }
        siz[z].push_back(id);
        return z;
    }
    void init()
    {
        for(int i=2;i<=O;i++){
            g[link[i]].push_back(i);
        }
    }
    int num[N];
    void dfs(int x,int fa){
        in[x]=++tim;
        num[tim]=x;
        for(auto i:g[x]){
            if(fa==i)continue;
            dfs(i,x);
        }
        out[x]=tim;
        qry[x] = {x,in[x],out[x]};
    }
    int lst[N];
    void cal()
    {
        init();
        dfs(1,-1);
        int now = 1;
        sort(qry+1,qry+1+O,[&](QU x,QU y){ return x.r<y.r; });
        for(int i = 1; i <= O; i++){
            for(auto x : siz[num[i]]){
                if(lst[x]) add(lst[x],-1);
                add(i,1),lst[x] = i;
            }
            while(now<=O&&qry[now].r==i){
                ans[qry[now].id] = query(i)-query(qry[now].l-1);
                ++now;
            }
        }
        ll res = 0;
        for(int i = 2; i <= O; i++){
            if(ans[i]==n){
                res += maxlen[i]-maxlen[link[i]];
            }
        }
        cout<<res<<'\n';
    }
} SAM;

int nx[maxn];
int get_loop(string s)
{
    int len=s.size();
    for(int i=0;i<=len+1;i++)nx[i]=0;
    nx[0] = -1;
    int i = 0, j = -1;
    while (i < len){
        if (j == -1 || s[i] == s[j]) nx[++i] = ++j;
        else j = nx[j];
    }
    int now = len-nx[len];
    if(len%now==0)return now;
    return len;
}
int getMin(string s,int len)
{
    int i = 0, j = 1, l;
    while(i < len && j < len){
        for(l = 0; l < len; l++)
            if(s[(i + l) % len] != s[(j + l) % len]) break;
        if(l >= len) break;
        if(s[(i + l) % len] > s[(j + l) % len]){
            if(i + l + 1 > j) i = i + l + 1;
            else i = j + 1;
        }
        else if(j + l + 1 > i) j = j + l + 1;
        else j = i + 1;
    }
    return i < j ? i : j;
}
string s[maxn];
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cin >> n;
    ans = 0;
    for(int i=0;i<n;i++)
    {
        cin>>s[i];
        int ml=get_loop(s[i]);
        int idx=getMin(s[i],ml);
        s[i]=s[i].substr(idx,ml-idx)+s[i].substr(0,idx);
    }
    sort(s,s+n);
    n=unique(s,s+n)-s;
    if(n==1){
        cout<<-1<<'\n';
        return 0;
    }
    int minid = 0, maxid = 0;
    for (int i=0;i<n;i++){
        if (s[i].length() < s[minid].length()) minid = i;
        if (s[i].length() > s[maxid].length()) maxid = i;
    }
    int len = s[minid].length();
    int target = s[maxid].length() * 2;
    int cnt=target/len+1;
    int last=1;
    while(cnt--){
        for(int i=0;i<len;i++){
            last = SAM.insert(s[minid][i] - 'a', last, minid);
        }
    }
    for(int i=0;i<n;i++){
        if(i==minid)continue;
        last=1;
        for(auto j:s[i]){
            last=SAM.insert(j-'a',last,i);
        }
        for(auto j:s[i]){
            last=SAM.insert(j-'a',last,i);
        }
    }
    SAM.cal();
    return 0;
}
posted @ 2020-08-11 09:56  Zeronera  阅读(183)  评论(0)    收藏  举报