随笔分类 - ACM
摘要:小希的迷宫 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 22224 Accepted Submission(s): 6801 Problem Description上次Gardon的迷宫城堡小希玩了很久(见Problem B),现在她也想设计...
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摘要:Leftmost Digit Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 1982 Accepted Submission(s): 884 Problem Description Given a positive integer N, y...
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摘要:Fibonacci Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2087 Accepted Submission(s): 999 Problem Description 2007年到来了。经过2006年一年的修炼,数学神童zouyu终于把0...
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摘要:动态规划算法解LCS问题 1 最长公共子序列的结构 最长公共子序列的结构有如下表示: 设序列X=和Y=的一个最长公共子序列Z=,则: 1> 若 xm=yn,则 zk=xm=yn,且Zk-1是Xm-1和Yn-1的最长公共子序列; 2> 若 xm≠yn且 zk≠xm ,则 Z是 Xm-1和 Y的最长公共子序列; 3> 若 xm≠yn且 zk≠yn ,则 Z是 X和 Yn-1的最长公共子序...
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摘要:How many prime numbers Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5139 Accepted Submission(s): 1684 Problem Description Give you a lot of...
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摘要:最小公倍数 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2010 Accepted Submission(s): 1543 Problem Description 给定两个正整数,计算这两个数的最小公倍数。 I...
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摘要:Beat Time Limit: 6000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 304 Accepted Submission(s): 199 Problem Description Zty is a man that ...
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摘要:并查集系列题目:http://acm.hdu.edu.cn/problemclass.php?id=721 畅通工程 Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 20380 Accepted Submission(s): 105...
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摘要:最短路Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 18542 Accepted Submission(s): 7897 Proble...
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摘要:畅通工程续Time Limit: 3000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 17034Accepted Submission(s): 5832Problem Desc...
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摘要:设B0=1,当k>0时,定义这些Bi(i=0, 1,…, k)被称为伯努利数。按定义,自然得出:B1=-,B2=,B3=0,B4=-,B5=0,B6=,B7=0,B8=-,…。伯努利数是瑞士数学家雅各布·伯努利引入的数,出自于他的著作《猜度术》(1713)。除了B1外,当k为奇数时,Bk=0;当k为偶数时,B2, B6, B10,…是正分数;B4, B8, B12,…是负分数。雅各布·伯努利引入伯努利数的目的是解决所谓“等幂和”的问题:求Sk(n)=1k+2k+…+nk对于S1(n)=1+2+3+…+n=n(n+1)S2(n)=12+22+32+…+n2=n(n+1)(2n
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摘要:The Grand DinnerTime Limit:5000MSMemory Limit:Unknown64bit IO Format:%lld & %llu[Submit] [Go Back] [Status]DescriptionProblem D The Grand DinnerInput...
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摘要:Problem C Add Again Input:Standard InputOutput:Standard OutputSummation of sequence of integers is always a common problem in Computer Science. Rather than computing blindly, some intelligent techniques make the task simpler. Here you have to find the summation of a sequence of integers. The sequenc
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摘要:Sum of Cubes Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 815 Accepted Submission(s): 182 Problem Description According to Goldbach’s conjecture...
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摘要:Problem B.Last Digit Background Give you a integer number N (1 2: #include 3: using namespace std; 4: const int maxn=101; 5: int sum[maxn]; 6: int myFun(int n){ 7: int ans=1; ...
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摘要:Elevator Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 38423 Accepted Submission(s): 20967 Problem Description The highest building in our city h...
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摘要:Let the Balloon Rise Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 65028 Accepted Submission(s)
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