摘要: 模运算与基本四则运算有些相似,但是除法例外。其规则如下: (a + b) % p = (a % p + b % p) % p (a - b) % p = (a % p - b % p) % p (a * b) % p = (a % p * b % p) % p a ^ b % p = ((a % p 阅读全文
posted @ 2017-05-22 20:43 ZERO- 阅读(1648) 评论(0) 推荐(0)
摘要: C. Do you want a date? time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output time limit per te 阅读全文
posted @ 2017-05-22 20:34 ZERO- 阅读(160) 评论(0) 推荐(0)
摘要: B. Summer sell-off time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output B. Summer sell-off tim 阅读全文
posted @ 2017-05-22 20:32 ZERO- 阅读(340) 评论(0) 推荐(0)
摘要: A. Straight «A» time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output A. Straight «A» time limi 阅读全文
posted @ 2017-05-22 20:29 ZERO- 阅读(527) 评论(0) 推荐(0)
摘要: 最近从博客上看到了一个fmod函数,结果又蹦出来一个modf函数 fmod()函数: 头文件:#include<math.h> C库函数。。。 fmod()用来对浮点数进行取模(求余),原型为:float fmod(float x)。 设x=k*n+h,则返回值为h(h和x的符号相同)。 fmod( 阅读全文
posted @ 2017-05-14 19:49 ZERO- 阅读(27911) 评论(2) 推荐(3)
摘要: A. Vicious Keyboard time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A. Vicious Keyboard 阅读全文
posted @ 2017-05-05 23:32 ZERO- 阅读(543) 评论(9) 推荐(0)
摘要: A. The New Year: Meeting Friends time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output A. The N 阅读全文
posted @ 2017-05-01 18:06 ZERO- 阅读(274) 评论(0) 推荐(0)
摘要: Rightmost Digit Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 55522 Accepted Submission(s): 209 阅读全文
posted @ 2017-05-01 17:16 ZERO- 阅读(2108) 评论(4) 推荐(1)
摘要: Party All the Time Time Limit: 6000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5462 Accepted Submission(s): 1 阅读全文
posted @ 2017-04-17 21:11 ZERO- 阅读(279) 评论(0) 推荐(0)
摘要: Can you find it? Time Limit: 10000/3000 MS (Java/Others) Memory Limit: 32768/10000 K (Java/Others)Total Submission(s): 42890 Accepted Submission(s): 1 阅读全文
posted @ 2017-04-17 21:07 ZERO- 阅读(142) 评论(0) 推荐(0)