2019-PTA模拟赛-L1-3 后天(三目表达式-仅代码)
Code:
#include<iostream>
using namespace std;
int main(){
int d;
cin >> d;
int res = (d + 2) % 7 == 0 ? 7 : (d + 2) % 7;
cout << res;
return 0;
}
Code:
#include<iostream>
using namespace std;
int main(){
int d;
cin >> d;
int res = (d + 2) % 7 == 0 ? 7 : (d + 2) % 7;
cout << res;
return 0;
}