2021年8月20日
摘要: SELECT name AS Customers FROM Customers WHERE Customers.Id not in (SELECT DISTINCT CustomerId FROM Orders) 阅读全文
posted @ 2021-08-20 22:23 一仟零一夜丶 阅读(18) 评论(0) 推荐(0)
摘要: # Write your MySQL query statement below SELECT Email FROM #获取Email个数的表 (SELECT Email,COUNT(Email) AS c FROM Person GROUP BY Email) as e WHERE e.c>1 阅读全文
posted @ 2021-08-20 17:06 一仟零一夜丶 阅读(44) 评论(0) 推荐(0)
摘要: SELECT `name` as Employee FROM Employee AS e1, #获取一个还有经理id和Salary的表 (SELECT id,Salary FROM Employee WHERE id IN (SELECT ManagerId FROM Employee WHERE 阅读全文
posted @ 2021-08-20 16:39 一仟零一夜丶 阅读(34) 评论(0) 推荐(0)