【ZJOI2009】【Codevs 2347】假期的宿舍

http://codevs.cn/problem/2347/

Solution

二分图板子

连边:i认识j并且j是在校有床 i→j+n

        i有床i→i+n

还有就是找要在学校的人,1.有床不回2.没床的(一定来探望)

记录一下二分图最大匹配是否等于要在校的学生即可

福利数据

IN

2

12
0 1 1 0 1 1 1 0 1 0 0 1
1 1 0 1 1 1 1 1 0 1 1 1
0 0 0 1 1 0 0 1 0 0 0 0
0 0 0 0 0 0 0 0 1 1 0 0
0 0 0 0 0 0 1 0 0 1 0 0
1 0 0 0 0 0 0 0 0 0 0 0
1 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 1 1 0 0 0
0 0 1 0 0 0 0 0 0 0 0 1
1 0 0 0 0 1 0 0 0 0 0 0
0 1 0 0 0 1 0 0 0 0 0 0
0 1 1 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 1
0 0 0 0 0 0 1 0 0 0 1 0
12
0 1 1 1 1 1 1 0 1 1 1 1
1 1 0 1 1 1 1 0 1 1 1 1
0 0 0 1 0 0 0 0 0 0 0 0
0 0 0 1 1 0 0 0 0 0 0 0
0 0 0 0 0 0 0 1 0 0 0 0
1 1 0 0 1 0 0 1 0 0 0 0
0 1 0 1 0 1 0 0 0 0 0 0
0 0 0 0 1 0 0 0 0 1 1 0
0 0 0 0 0 0 0 0 0 0 0 1
0 0 1 1 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0 0 0
0 0 0 0 0 0 1 0 0 0 0 0
12
1 1 1 0 1 1 0 1 1 0 1 1
0 1 1 1 0 1 1 1 1 1 1 1
0 0 0 0 0 0 0 1 0 0 0 0
0 0 0 0 0 1 0 0 0 0 0 0
0 0 0 0 0 0 1 0 0 0 0 1
0 0 0 0 1 0 1 0 1 1 0 0
0 0 0 1 0 0 0 0 1 0 0 0
0 1 0 0 0 0 0 0 0 0 0 0
0 0 1 1 0 0 0 0 1 0 0 0
1 0 0 0 0 0 0 0 0 0 0 0
0 0 0 1 1 0 1 0 0 0 0 1
0 0 0 1 0 0 0 0 0 0 1 0
0 0 0 0 0 0 0 0 0 1 0 0
0 0 1 0 0 0 0 0 1 0 0 0

OUT

T_T
T_T
^_^

Code

// This file is made by YJinpeng，created by XuYike's black technology automatically.
// Copyright (C) 2016 ChangJun High School, Inc.
// I don't know what this program is.

#include <iostream>
#include <vector>
#include <algorithm>
#include <cstring>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#define MOD 1000000007
#define INF 1e9
using namespace std;
typedef long long LL;
const int MAXN=100010;
const int MAXM=100010;
inline int gi() {
	register int w=0,q=0;register char ch=getchar();
	while((ch<'0'||ch>'9')&&ch!='-')ch=getchar();
	if(ch=='-')q=1,ch=getchar();
	while(ch>='0'&&ch<='9')w=w*10+ch-'0',ch=getchar();
	return q?-w:w;
}
struct Hungarian_dfs{
    static const int N=110;
    int cnt,n;
    int match[N],a[N],c[N];
    vector<int>b[N];int f[N];
    inline void add(int u,int v){b[u].push_back(v);}
    bool dfs(int x){
        if(f[x]==cnt)return 0;
        int num=b[x].size();f[x]=cnt;
        for(int i=0;i<num;i++){
            int nex=b[x][i];
            if(match[nex]==-1||dfs(match[nex])){
                match[x]=nex;match[nex]=x;return 1;
            }
        }
        return 0;
    }
    void Work(){
        int T=gi();
        while(T--){
            n=gi();int now=0;
            for(int i=1;i<=n;i++)a[i]=gi(),b[i].clear();
            for(int i=1;i<=n;i++){
                c[i]=gi()?a[i]:0;
                if(!c[i])now++;
                if(a[i])add(i,i+n);
            }
            for(int i=1;i<=n;i++)
                for(int j=1;j<=n;j++)
                    if(gi()&&a[j])add(i,j+n);//gi()放前面 逻辑短路
            memset(f,false,sizeof(f));int ans=0;
            for(int i=1;i<N;i++)match[i]=-1;
            for(int i=1;i<=n;i++)
                if(match[i]==-1&&!c[i]){
                    ++cnt;if(dfs(i))++ans;else break;
                }
            printf(ans==now?"^_^\n":"T_T\n");
        }
    }
}d;
int main()
{
	freopen("2347.in","r",stdin);
	freopen("2347.out","w",stdout);
	d.Work();
	return 0;
}