摘要: 1 import java.util.Scanner; 2 3 class Read{ 4 String s; 5 Read(String a){ 6 s = a; 7 } 8 int pos = 0; 9 char ReadChar(){ 10 pos++; 11 return s.charAt( 阅读全文
posted @ 2017-03-22 16:13 Xycdada 阅读(215) 评论(0) 推荐(0)
摘要: 最短路 Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 60771 Accepted Submission(s): 26759 Problem D 阅读全文
posted @ 2017-03-22 09:57 Xycdada 阅读(177) 评论(0) 推荐(0)