随笔分类 - ACM日常刷题
摘要：1 include<iostream> 2 3 using namespace std; 4 5 int num[5]={1,2,3,4,5}; 6 int sum; 7 8 void swap(int *p,int *q) 9 { 10 int m = *p; 11 *p=*q; 12 *q=m;
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摘要：Snowflake Snow Snowflakes Time Limit: 4000MS Memory Limit: 65536K Total Submissions: 40969 Accepted: 10792 Description You may have heard that no two
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摘要：恢复内容开始 B. Counting-out Rhyme time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output n children a
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摘要：1 #include<iostream> 2 #include<set> 3 #include<string> 4 #include<cstring> 5 6 using namespace std; 7 8 int num[10]={10,9,8,7,6,5,4,3,2,1}; 9 10 void
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摘要：下沙的沙子有几粒？ Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4326 Accepted Submission(s): 2268 Probl
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摘要：1 import java.util.Scanner; 2 3 class Read{ 4 String s; 5 Read(String a){ 6 s = a; 7 } 8 int pos = 0; 9 char ReadChar(){ 10 pos++; 11 return s.charAt(
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摘要：最短路 Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 60771 Accepted Submission(s): 26759 Problem D
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摘要：1 #include<iostream> 2 #include<cstring> 3 4 #define MAX_N 10000000 5 6 using namespace std; 7 8 bool flag[MAX_N]; 9 int prime[MAX_N]; 10 11 void solv
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摘要：看病要排队 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 9083 Accepted Submission(s): 3848 Problem D
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摘要：Let the Balloon Rise Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 116867 Accepted Submission(s
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摘要：Integer Inquiry Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 19879 Accepted Submission(s): 525
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摘要：恢复内容开始 B - Oulipo The French author Georges Perec (1936�C1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulip
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摘要：C - 剪花布条 一块花布条，里面有些图案，另有一块直接可用的小饰条，里面也有一些图案。对于给定的花布条和小饰条，计算一下能从花布条中尽可能剪出几块小饰条来呢？ Input 输入中含有一些数据，分别是成对出现的花布条和小饰条，其布条都是用可见ASCII字符表示的，可见的ASCII字符有多少个，布条的
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摘要：数据结构中栈的应用 1 #include<iostream> 2 #include<cstring> 3 4 using namespace std; 5 6 char str[1000]; 7 char ans[1000]; 8 struct fu 9 { 10 char ff[1000]; 11
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摘要：一道贪心水题，思想就是从最左边的点开始，距离为r以内的最远的点为标记点，然后不断重复着过程。 1 1 // 2 2 // main.cpp 3 3 // poj 3069 4 4 // 5 5 // Created by dada on 2017/2/15. 6 6 // Copyright © 2
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摘要：贪心，这是挑战程序设计竞赛书上的一种方法，略微奇特的贪心。用到了二叉树的思想，还是很有意思的。 1 // 2 // main.cpp 3 // poj 3253 4 // 5 // Created by dada on 2017/2/15. 6 // Copyright © 2017年 dada.
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摘要：寻根 Time Limit : 3000/1000ms (Java/Other) Memory Limit : 65535/32768K (Java/Other) Total Submission(s) : 118 Accepted Submission(s) : 29 Font: Times Ne
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摘要：upupup Time Limit : 3000/1000ms (Java/Other) Memory Limit : 65535/32768K (Java/Other) Total Submission(s) : 239 Accepted Submission(s) : 14 Font: Time
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摘要：Tree Time Limit: 6000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2333 Accepted Submission(s): 710 Problem Des
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摘要：最小生成树prime算法 Jungle Roads Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7013 Accepted Submissio
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