摘要:
#include<iostream> using namespace std; typedef long long ll; ll q_mul(ll a, ll b, ll p) { ll ret = 0; while (b) { if (b&1)(ret += a)%=p; b>>=1; (a<<= 阅读全文
摘要:
简单线段树操作 咕咕咕 Transformation HDU - 4578 vj talk is cheap, chow the code. #include <iostream> #include <cstring> using namespace std; typedef long long l 阅读全文
摘要:
LCM 最小公倍数,求得方式为 \((a*b)/gcd(a, b)\) 从本质上看,是由$a$的全部质因子最高位和$b$的全部质因子并起来的结果 \(a = p _{a}^{k1} p _{b}^{k2} p _{c}^{k3}\) \(b = p _{a}^{k4} p _{b}^{k5} p _ 阅读全文