实验3
任务一
#include <stdio.h> long long fac(int n); int main() { int i, n; printf("Enter n: "); scanf_s("%d", &n); for (i = 1; i <= n; ++i) printf("%d! = %lld\n", i, fac(i)); return 0; } long long fac(int n) { static long long p = 1; p = p * n; return p; }
#include <stdio.h> long long fac(int n); int main() { int i, n; printf("Enter n: "); scanf_s("%d", &n); for (i = 1; i <= n; ++i) printf("%d! = %lld\n", i, fac(i)); return 0; } long long fac(int n) { static long long p = 1; printf("p = %lld\n", p); p = p * n; return p;
#include <stdio.h> int func(int, int); int main() { int k = 4, m = 1, p1, p2; p1 = func(k, m); p2 = func(k, m); printf("%d,%d\n", p1, p2); return 0; } int func(int a, int b) { static int m = 0, i = 2; i += m + 1; m = i + a + b; return (m); }
static变量特性:函数退出时,变量始终存在,但不能被其他函数使用,当再次进入该函数时,将保存上次的结果。
任务二
#include<stdio.h> void printsymbol(int n, char symbol); int main() { int n; char symbol; while (scanf_s("%d %c", &n, &symbol) != EOF) { printsymbol(n, symbol); printf("\n"); } return 0; } void printsymbol(int n, char symbol) { int i; for (i = 0; i < n; i++) printf("%c", symbol); return; }
#include<stdio.h> void printsymbol(int n, char symbol); int main() { int n; char symbol; while (scanf_s("%d %c", &n, &symbol) != EOF) { printsymbol(n, symbol); printf("\n"); } return 0; } void printsymbol(int n, char symbol) { while (n != -1) { if (n != 0) { printf("%c", symbol); n--; } else n = -1; } }
实验三
#include <stdio.h> long long fun(int n); int main() { int n; long long f; while (scanf_s("%d", &n) != EOF) { f = fun(n); printf("n = %d, f = %lld\n", n, f); } return 0; } long long fun(int n) { int t; if (n == 1) t = 1; else t = fun(n - 1) * 2 + 1; return t; }
实验四
#include <stdio.h> int isprime(int n); int main() { int a=0, i; for (i = 101; i < 201; i++) { if (!isprime(i)) { printf("%d ", i); a++; while (a % 10 == 0 && a != 0) { printf("\n"); break; } } } printf("\n101~200之间一共有%d个非素数", a); return 0; } int isprime(int n) { int i; for (int i = 2; i < (n + 4) / 2; i++) { if (n == 2) return 1; else if (n % i == 0) { return 0; break; } if (i == (n + 4) / 2 - 1 && n % i != 0) { return 1; } } }
实验五
#include <stdio.h> long fun(long s); int main() { long s, t; printf("Enter a number: "); while (scanf_s("%ld", &s) != EOF) { t = fun(s); printf("new number is: %ld\n\n", t); printf("Enter a number: "); } return 0; } long fun(long s) { long m, n=0; long i = 1; while (s > 0) { m = s % 10; if (m % 2 != 0) { n = n + m * i; i = i * 10; } s = s / 10; } return n; }
实验六
#include <stdio.h> double fun(int n); int main() { int n; double s; printf("Enter n(1~10): "); while (scanf_s("%d", &n) != EOF) { s = fun(n); printf("n = %d, s= %f\n\n", n, s); printf("Enter n(1~10): "); } return 0; } double fun(int n) { int i, a, b; double sum=0; a = 1; b = 1; for (i = 1; i <= n; i++) { b = b * i; sum = sum + 1.0 / b * a; a = a * (-1); } return sum; }
实验总结:对函数定义有更深刻的理解