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软件工程第三次作业(最大子段和)

求最大连续子数组和(最大子段和) 一、题目简介

给定n个整数(可能为负数)组成的序列a[1],a[2],a[3],…,a[n],求该序列如a[i]+a[i+1]+…+a[j]的子段和的最大值。当所给的整数均为负数时定义子段和为0,依此定义,所求的最优值为: Max{0,a[i]+a[i+1]+…+a[j]},1<=i<=j<=n
例如,当(a[1],a[2],a[3],a[4],a[5],a[6])=(-2,11,-4,13,-5,-2)时,最大子段和为20。
引用自《<a style="color:blue;text-decoration:none;"href="https://baike.baidu.com/item/%E6%9C%80%E5%A4%A7%E5%AD%90%E6%AE%B5%E5%92%8C">百度百科》

二、编写代码

<a style="color:blue;text-decoration:none;"href="https://dev.tencent.com/u/Ww-Yating/p/zuidahe/git">coding地址

def maxnum(number):
    if len(number)==0:
        return 0
    num=number.copy()
    max=0
    for i in range(1,len(number)):
        if num[i-1]>0:
            num[i]=num[i-1]+number[i]
        else:
            num[i]=number[i]
        if num[i]>max:
            max=num[i]
    return max

三、程序流程图 ![](https://img2018.cnblogs.com/blog/1648396/201904/1648396-20190418192715266-1378556042.png) 四、单元测试 1、测试代码
import unittest
from MAX import *

number1=[]
number2=[-2,11,-4,13,-5,-2]
number3=[-1,-2,-3,-4,-5]
number4=[-5,19,-9,4,-5]

class TestMathFunc(unittest.TestCase):
    def test_maxnum1(self):
        self.assertEqual(0, maxnum(number1),"Wrong!")

    def test_maxnum2(self):
        self.assertEqual(20, maxnum(number2),"Wrong!")

    def test_maxnum3(self):
        self.assertEqual(0, maxnum(number3),"Wrong!")

    def test_maxnum4(self):
        self.assertEqual(19, maxnum(number4),"Wrong!")

if __name__ == '__main__':
    unittest.main()

2、判定/条件覆盖测试

满足一下覆盖条件

len(number)==0

len(number)!=0

num[i]>0

num[i]<=0

num[i]>sum

num[i]<=sum

3、测试结果 ![](https://img2018.cnblogs.com/blog/1648396/201904/1648396-20190418200100021-643384693.png)
posted @ 2019-04-18 20:17  王雅婷  阅读(183)  评论(0编辑  收藏  举报