1049. Counting Ones (30)
摘要:
#include <iostream> using namespace std; int main() { int n; scanf("%d", &n); int low, mid, high, d = 1, res = 0; while(n >= d) { high = n / (d * 10); 阅读全文
posted @ 2025-11-23 17:08 王景迁 阅读(4) 评论(0) 推荐(0)
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