hdu 5562 Clarke and food（贪心）

Problem Description

Clarke is a patient with multiple personality disorder. One day, Clarke turned into a cook, was shopping for food. 
Clarke has bought n food. The volume of the ith food is vi. Now Clarke has a pack with volume V. He wants to carry food as much as possible. Tell him the maxmium number he can brought with this pack.

 

Input

The first line contains an integer T(1≤T≤10), the number of the test cases.
For each test case: 
The first line contains two integers n,V(1≤n≤105,1≤V≤109). 
The second line contains n integers, the ith integer denotes vi(1≤vi≤109).

 

Output

For each test case, print a line with an integer which denotes the answer.

 

Sample Input

1
3 5
1 3 4

 

Sample Output

2

 

 Hint: We can carry 1 and 3, the total volume of them is 5.

 

 

Source

BestCoder Round #62 (div.2)

 

贪心，将值从小到大排序后，一直选就可以了。

 

#pragma comment(linker, "/STACK:1024000000,1024000000")
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<math.h>
#include<algorithm>
#include<queue>
#include<set>
#include<bitset>
#include<map>
#include<vector>
#include<stdlib.h>
#include <stack>
using namespace std;
#define PI acos(-1.0)
#define max(a,b) (a) > (b) ? (a) : (b)
#define min(a,b) (a) < (b) ? (a) : (b)
#define ll long long
#define eps 1e-10
#define MOD 1000000007
#define N 100006
#define inf 1e12
int n,v;
int a[N];
int dp[N];
int dp_num[N];
int main()
{
   int t;
   scanf("%d",&t);
   while(t--){
      scanf("%d%d",&n,&v);
      for(int i=0;i<n;i++){
         scanf("%d",&a[i]);
      }
      sort(a,a+n);
      int ans=0;
      int index=0;
      while(v>0){
         if(v>=a[index]){
            v-=a[index];
            index++;
            ans++;
         }else{
            break;
         }

      }
      printf("%d\n",ans);
   }
    return 0;
}