import java.util.LinkedList;
import java.util.Queue;
/**
* 给定一个二叉树,找出其最大深度。
* <p>
* 二叉树的深度为根节点到最远叶子节点的最长路径上的节点数。
* <p>
* 说明: 叶子节点是指没有子节点的节点。
* <p>
* 示例:
* 给定二叉树 [3,9,20,null,null,15,7],
* <p>
* 3
* / \
* 9 20
* / \
* 15 7
* 返回它的最大深度 3
* <p>
* 来源:力扣(LeetCode)
* 链接:https://leetcode-cn.com/problems/maximum-depth-of-binary-tree
* 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
*/
public class MaxDepth {
//递归
public static int maxDepth(TreeNode root) {
if(null == root) return 0;
int leftDepth = maxDepth(root.left);
int rightDepth = maxDepth(root.right);
return Math.max(leftDepth,rightDepth) + 1;
}
public static class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode(int x) { val = x; }
public TreeNode(int val, TreeNode left, TreeNode right) {
this.val = val;
this.left = left;
this.right = right;
}
}
//广度优先算法
public static int MaxDepthV2(TreeNode root){
if(null == root){
return 0;
}
int maxDepth = 0;
Queue<TreeNode> queue = new LinkedList<TreeNode>();
queue.offer(root);
while (!queue.isEmpty()){
int size = queue.size();
while (size >0 ){
TreeNode node = queue.poll();
if(null != node.left){
queue.offer(node.left);
}
if(null != node.right){
queue.offer(node.right);
}
size--;
}
maxDepth++;
}
return maxDepth;
}
public static void main(String[] args) {
TreeNode treeNode1 = new TreeNode(15);
TreeNode treeNode2 = new TreeNode(7);
TreeNode treeNode3 = new TreeNode(9,treeNode1,treeNode2);
TreeNode treeNode4 = new TreeNode(20);
TreeNode treeNode5 = new TreeNode(3,treeNode3,treeNode4);
int maxDepth = MaxDepthV2(treeNode5);
System.out.println("RESULT ====" + maxDepth);
}
}