codeforces 828 C. String Reconstruction（思维+优先队列）

题目链接：http://codeforces.com/contest/828/problem/C

 

题解：有点意思的题目，可用优先队列解决一下具体看代码理解。或者用并查集或者用线段树都行。

#include <iostream>
#include <cstring>
#include <queue>
#include <vector>
#include <cstdio>
#include <map>
#include <string>
#include <vector>
using namespace std;
const int M = 2e6 + 10;
const int N = 1e5 + 10;
int pos;
struct TnT {
    int sta, ed , num;
    TnT() {}
    TnT(int sta , int ed , int num):sta(sta), ed(ed), num(num) {}
    bool operator <(const TnT &a) const {
        return ed - pos > a.ed - pos;
    }
};
priority_queue<TnT>q;
vector<int>vc[M];
string s[N];
int main() {
    int n, k, pp;
    scanf("%d" , &n);
    int Max = 1;
    for(int i = 1 ; i <= n ; i++) {
        cin >> s[i];
        cin >> k;
        int len = s[i].size();
        for(int j = 0 ; j < k ; j++) {
            cin >> pp;
            Max = max(Max , pp + len - 1);
            vc[pp - 1].push_back(i);
        }
    }
    for(pos = 0 ; pos < Max ; pos++) {
        int len = vc[pos].size();
        for(int i = 0 ; i < len ; i++) {
            int L = s[vc[pos][i]].size();
            q.push(TnT(pos , pos + L - 1 , vc[pos][i]));
        }
        if(q.empty()) cout << 'a';
        else {
            cout << s[q.top().num][pos - q.top().sta];
            while(!q.empty()) {
                if(q.top().ed == pos) q.pop();
                else break;
            }
        }
    }
    cout << endl;
    return 0;
}