获取URL参数JS函数
摘要://获取URL参数function getUrlParam(paramName) { var href = window.location.href; var url = decodeURI(href); var idx = url.indexOf("?"); var params = url.su
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posted @ 2019-05-22 10:11
posted @ 2019-05-22 10:11
posted @ 2019-05-17 15:34