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class Solution { public: TreeNode* buildTree(vector<int>& inorder, vector<int>& postorder) { return reBuild(inorder, postorder); } TreeNode* reBuild(v 阅读全文
posted @ 2022-09-24 15:40
Syukuu
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class Solution { public: bool isSymmetric(TreeNode* root) { if (root == nullptr) return true; return Preocess(root->left, root->right); } bool Preoces 阅读全文
posted @ 2022-09-24 15:38
Syukuu
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思路: 直接前序遍历两个树获得叶子节点,然后对vector容器进行比较 class Solution { public: bool leafSimilar(TreeNode* root1, TreeNode* root2) { vector<int> r1,r2; getLeaf(root1,r1) 阅读全文
posted @ 2022-09-24 15:38
Syukuu
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