摘要: 1 =60 && time()-$time=3600 && time()-$time=86400){18 $day=intval((time()-$time)/86400);19 $hour=intval((time()-$time)/3600-$day*24);20 $min=intval(((time()-$time)-$hour*3600-$day*86400)/60);21 $sec=(time()-$time)-$min*60-$hour*3600-$day*86400;22 $result=$day.... 阅读全文
posted @ 2013-07-24 08:18 烧饼程序猿 阅读(209) 评论(0) 推荐(0)