POJ 2311 博弈
摘要:
1 #include 2 #include 3 #include 4 using namespace std; 5 6 int sg[205][205]; 7 8 int solve(int w,int h){ 9 if(sg[w][h]!=-1){10 return ... 阅读全文
posted @ 2013-09-07 20:02 Stomach_ache 阅读(137) 评论(0) 推荐(0)
posted @ 2013-09-07 20:02 Stomach_ache 阅读(137) 评论(0) 推荐(0)
posted @ 2013-09-07 18:59 Stomach_ache 阅读(463) 评论(0) 推荐(0)
posted @ 2013-09-07 18:54 Stomach_ache 阅读(101) 评论(0) 推荐(0)