摘要:
n = 0 for i in range(1, 5): for j in range(1, 5): for k in range(1, 5): if(i != k) and (i != j) and (j != k): print(i, j, k) n += 1 print('共有%s种' % n) 阅读全文
摘要:
#include<stdio.h> void main() { int n, i, j; for (n = 1000; n < 10000; n++) { i = n / 100; j = n % 100; if (n == ((i + j) * (i + j))) printf("%d\n", n 阅读全文
摘要:
break_out = False while 1: s = [] for i in range(3): x = int(input('请输入一个数:\n')) if x == -1: # 设计一个退出循环的条件 break_out = True break s.append(x) if break 阅读全文
摘要:
def SlowSnail(n): while n != 1: # 循环保证递归 for index in range(2, n + 1): if n % index == 0: n //= index # n 等于 n//index if n == 1: print(index) else: pr 阅读全文
摘要:
while 1: def fib(n): if n == 1 or n == 2: return 1 return fib(n - 1) + fib(n - 2) n = int(input('请输入所求数的索引:\n')) if n == -1: # 设置跳出循环的条件 break print(' 阅读全文