摘要: 思路: $\Pi_{i=1}^n\Pi_{j=1}^m f[gcd(i,j)]$ $=\Pi_{d=1}^n\Pi_{i=1}^{\lfloor\frac{n}{d}\rfloor}\Pi_{j=1}^{\lfloor\frac{m}{d}\rfloor}f[d]*(gcd(i,j)==1)$ $\ 阅读全文
posted @ 2017-04-13 11:20 SiriusRen 阅读(349) 评论(0) 推荐(0) 编辑