摘要: ⑤(BZOJ 3560) $\Sigma_{i_1|a_1}\Sigma_{i_2|a_2}\Sigma_{i_3|a_3}\Sigma_{i_4|a_4}...\Sigma_{i_n|a_n}\phi(i_1i_2i_3i_4...i_n)$$\phi()$是积性函数$\phi(p^k)=p^{k 阅读全文
posted @ 2017-04-12 23:58 SiriusRen 阅读(400) 评论(0) 推荐(0) 编辑