摘要: 题目-1 from Crypto.Util.number import * from gmpy2 import * from secret import flag flag = "******" e = 65537 m = bytes_to_long(flag) p = getPrime(1024) 阅读全文
posted @ 2025-04-23 15:04 sevensnight 阅读(186) 评论(0) 推荐(0)