关于模拟题(部分代码)
摘要:
// fluorite for (int i = 0; i < k; i++) { for (int j = 0; j < 5; j++) { for (int j2 = 0; j2 < 5; j2++) { if (f(c[i][0] + (j - 2), c[i][1] + (j2 - 2), 阅读全文
posted @ 2022-05-30 20:40 Hex酱 阅读(27) 评论(1) 推荐(0)
posted @ 2022-05-30 20:40 Hex酱 阅读(27) 评论(1) 推荐(0)