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这是一个求一个排序的下一个排列的函数,可以遍历全排列,要包含头文件<algorithm>与之完全相反的函数还有prev_permutation (1) int 类型的next_permutation int main(){ int a[3];a[0]=1;a[1]=2;a[2]=3; do{cout 阅读全文
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D - Kadj Squares Time Limit:2000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u Submit Status D - Kadj Squares Submit Status Description In this 阅读全文
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A - Toy Storage Time Limit:1000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u Submit Status A - Toy Storage Submit Status Description Mom and d 阅读全文
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B - TOYS Time Limit:2000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u Submit Status B - TOYS Submit Status Description Calculate the number of 阅读全文
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E - Domination Time Limit:8000MS Memory Limit:131072KB 64bit IO Format:%lld & %llu Submit Status E - Domination Submit Status Description Edward is th 阅读全文
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D - LOOPS Time Limit:5000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u Submit Status D - LOOPS Submit Status Description Akemi Homura is a Mah 阅读全文
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C - Collecting Bugs Time Limit:10000MS Memory Limit:64000KB 64bit IO Format:%I64d & %I64u Submit Status C - Collecting Bugs Submit Status Description 阅读全文