ATM管理系统

一、作业信息
[博客班级] 软件工程
[作业要求] 作业要求
[作业目标] 熟悉ATM机的运行系统并创建；
[学号] 318071334
二、题目要求
编写一个ATM管理系统，语言不限，要求应包括以下主要功能：
（1）开户，销户
（2）查询账户余额
（3）存款
（4）取款
（5）转账（一个账户转到另一个账户）等...
三、代码提交

#include <iostream>
#include <string>
#include <cstdlib>
#include <cstdio>
using namespace std;

typedef struct
{
	string name;			//用户名
	string password;		//密码
	string account;	 //账户
	float money;			//余额
}AccountNode;

typedef struct node
{
	AccountNode acc;
	struct node* next;
}Node;

void Menu();					//主菜单
void CreateAccount(Node*& head);		//注册账户
void Login(Node* head);				//登录
bool CloseAccount(Node*& head);			//注销账户
void LoginMenu();				//登录菜单
Node* Find(Node* head, string accountNumber);	//根据账号找客户

void Menu()//主菜单
{
	printf("\n\n\n\t\t\t\t\t *************************\n");
	printf("\t\t\t\t\t*\tATM管理系统\t *\n");
	printf("\t\t\t\t\t*\t  1.注册账户\t *\n");
	printf("\t\t\t\t\t*\t  2.登录\t *\n");
	printf("\t\t\t\t\t*\t  3.注销账户\t *\n");
	printf("\t\t\t\t\t*\t  4.退出\t *\n");
	printf("\t\t\t\t\t *************************\n");
	printf("\t\t\t\t\t\t\t请选择：");
}

void CreateAccount(Node*& head)
{
	printf("\n\n\n\t\t\t\t\t请输入您的姓名：");
	string name;
	cin >> name;

	printf("\n\t\t\t\t\t请设置您的银行卡密码：");
	string password;
	cin >> password;

	printf("\n\t\t\t\t\t请再次输入您的银行卡密码：");
	string repassword;
	cin >> repassword;

	//判断两次输入的密码是否一致
	while (password != repassword) 
	{
		printf("\n\t\t\t\t\t两次输入密码不一致，请重新输入：");
		cin >> repassword;
	}

	//随机生成银行账号
	char temp[20];//0000 0000 0000 0000 0 0
	string account;
	srand((unsigned int)time(NULL));
	sprintf(temp, "%d%d%d%d%d%d", rand() % 9000 + 1000, rand() % 9000 + 1000, rand() % 9000 + 1000, rand() % 9000 + 1000, rand() % 10, rand() % 10);//sprintf格式化字符串 
	account = temp;

	Node* pNode = new Node;
	pNode->acc.name = name;
	pNode->acc.password = password;
	pNode->acc.account = account;
	pNode->acc.money = 0;
	pNode->next = NULL;

	Node* p = head;
	while (p != NULL && p->next != NULL)
		p = p->next;
	if (head == NULL)
		head = pNode;
	else
		p->next = pNode;

	printf("\n\n\t\t\t\t\t恭喜您，开户成功！\n");
	cout << "\n\t\t\t\t\t您的账号为：" << account << endl;
}

void LoginMenu()
{
	printf("\n\n\n\t\t\t********************\n");
	printf("\t\t\t\t\t*\t  1.存款\t *\n");
	printf("\t\t\t\t\t*\t  2.取款\t *\n");
	printf("\t\t\t\t\t*\t  3.转账\t *\n");
	printf("\t\t\t\t\t*\t  4.查询余额\t *\n");
	printf("\t\t\t\t\t*\t  5.修改密码\t *\n");
	printf("\t\t\t\t\t*\t  6.退出\t *\n");
	printf("\t\t\t\t\t ********************\n");
	printf("\t\t\t\t\t\t\t请选择：");
}

void Login(Node* head)
{
	string account;
	string password;
	printf("\n\n\n\t\t\t\t\t请输入您的账号：");
	cin >> account;
	Node* p = Find(head, account);
	if (!p)
	{
		printf("\n\t\t\t\t\t账号输入有误！");
		return;
	}
	printf("\n\t\t\t\t\t请输入您的密码：");
	cin >> password;
	while (p->acc.password != password) 
	{
		printf("\n\t\t\t\t\t密码错误，请重新输入：");
		cin >> password;
	}
	while (1)
	{
		system("cls");
		LoginMenu();
		int choice;
		string otheraccount;
		double money;
		string newPassword;
		Node* temp;
		cin >> choice;
		switch (choice)
		{
		case 1:
			printf("\n\n\t\t\t\t\t请输入您的存款金额：");
			cin >> money;
			p->acc.money += money;
			printf("\n\t\t\t\t\t\t存款成功！\n");
			break;
		case 2:
			printf("\n\n\t\t\t\t\t请输入您的取款金额：");
			cin >> money;
			if (money > p->acc.money)
				printf("\n\t\t\t\t\t\t余额不足！\n");
			else {
				p->acc.money -= money;
				printf("\n\t\t\t\t\t\t取款成功！\n");
			}
			break;
		case 3:
			printf("\n\n\t\t\t\t\t请输入您的转账的账号：");
			cin >> otheraccount;
			printf("\n\t\t\t\t\t请输入您的转账金额：");
			cin >> money;
			temp = Find(head, otheraccount);
			if (!temp) {
				printf("\n\t\t\t\t\t账号输入有误！");
				system("pause");
				return;
			}
			p->acc.money -= money;
			temp->acc.money += money;
			printf("\n\t\t\t\t\t\t转账成功！\n");
			break;
		case 4:
			printf("\n\n\t\t\t\t\t您的余额为：%.2f\n", p->acc.money);
			break;
		case 5:
			printf("\n\n\t\t\t\t\t请输入您的新密码：");
			cin >> newPassword;
			p->acc.password = newPassword;
			printf("\n\t\t\t\t\t\t密码修改成功！\n");
			break;
		case 6:
			return;
		default:
			printf("\t\t\t\t\t\t\t输入有误！\n");
		}
		system("pause");
	}
}

Node* Find(Node* head, string account)
{
	Node* p = head;
	while (p != NULL) 
	{
		if (p->acc.account == account)
			break;
		p = p->next;
	}
	return p;
}

bool closeaccount(Node*& head)
{
	string account;
	printf("\n\n\t\t\t\t\t请输入您要注销的账号：");
	cin >> account;
	Node* p = head, * q;
	if (p != NULL && p->acc.account == account)
	{
		head = p->next;
		free(p);
		printf("\t\t\t\t\t\t\t注销成功！\n");
		return true;
	}
	q = p;
	p = p->next;
	while (p != NULL) {
		if (p->acc.account == account) 
		{
			q->next = p->next;
			free(p);
			printf("\t\t\t\t\t\t\t注销成功！\n");
			return true;
		}
		q = p;
	}
	return false;
}

int main()
{
	Node* head = NULL;

	while (1) 
	{
		system("cls");
		Menu();
		int choice;
		cin >> choice;
		switch (choice)
		{
		case 1:
			CreateAccount(head);
			break;
		case 2:
			Login(head);
			break;
		case 3:
			CloseAccount(head);
			break;
		case 4:
			return 0;
		default:
			printf("\t\t\t\t\t\t\t输入有误！\n");
		}
		system("pause");
	}
	return 0;
}

运行截图：

psp2.1	任务内容	计划完成需要的时间（min）	实际完成需要的时间（min）
Planning	计划	30	45
Estimate	估计这个任务需要多少时间，并规划大致工作步骤	5	6
Development	开发	360	540
Analysis	需求分析（包括学习新技术	10	30
Design Spec	生成设计文档	15	40
Design Review	设计复审	5	10
Coding Standard	代码规范	3	5
Design	具体设计	10	50
Coding	具体编码	100	300
Code Review	代码复审	5	10
Test	测试（自我测试，修改代码，提交修改）	10	20
Reporting	报告	10	20
Test Report	测试报告	10	20
Size Measurement	计算工作量	3	5
Postmortem & Process Improvement Plan	事后总结，并提出过程改进计划	3	4

四、小结
本次aTm系统设计真是煞费苦心，大体的思路很清晰，但遇到文件的使用就直接gg了，通过这次的编码学到了很多。