10 2012 档案

hdu 4268 Alice and Bob
摘要：Alice and BobTime Limit: 10000/5000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1253Accepted Submission(s): 478Problem DescriptionAlice and Bob's game never ends. Today, they introduce a new game. In this game, both of them have N different rectangular cards res 阅读全文

posted @ 2012-10-11 19:59 Raining Days 阅读(228) 评论(0) 推荐(0)

hdu 1669 Jamie's Contact Groups
摘要：Jamie's Contact GroupsTime Limit: 15000/7000 MS (Java/Others)Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 225Accepted Submission(s): 63Problem DescriptionJamie is a very popular girl and has quite a lot of friends, so she always keeps a very long contact list in her cell phone. 阅读全文

posted @ 2012-10-11 09:02 Raining Days 阅读(299) 评论(0) 推荐(0)

poj 1240
摘要：题目链接：http://poj.org/problem?id=1240好久之前自己写的，今天拿出来看看，越看越喜欢。题目意思，已知前序遍历跟后序遍历，求树共有多少种形态。前一篇随笔中提到了一点。View Code #include <iostream>#include <stdio.h>#include <string.h>#include <stdlib.h>using namespace std;const int maxn=27;char s1[maxn],s2[maxn];int m,ans,pre;int zuhe(int cnt){ 阅读全文

posted @ 2012-10-01 14:31 Raining Days 阅读(234) 评论(0) 推荐(0)

组合数的求法
摘要：今天是国庆节，没有出去，因为之前一直都在学习数据结构的东西，把图论的东西忘的差不多，七天乐，乐图论。今天早上电脑无缘无故开不了机，没办法我把硬盘拆了又重装了一遍。昨晚看到个给出一棵K叉树的前序跟后序遍历，让算一下这个树一共有多少种形态。里面涉及到一点求组合数的知识，我把他弄上来，免的自己以后忘记了。 阅读全文

posted @ 2012-10-01 14:21 Raining Days 阅读(624) 评论(2) 推荐(0)

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