# 2032  杨辉三角

 1 #include <stdio.h>
2
3 int main(){
4     int s[31][31],i,j,n;
5     while(~scanf("%d",&n)){
6         for(i=0;i<n;i++){
7             for(j=0;j<=i;j++){
8                 if(j==0 || j==i){s[i][j]=1;}
9                 else{s[i][j]=s[i-1][j]+s[i-1][j-1];}
10             }
11         }
12         for(i=0;i<n;i++){
13             for(j=0;j<=i;j++){
14                 if(j==i){printf("%d\n",s[i][j]);}
15                 else{printf("%d ",s[i][j]);}
16             }
17         }
18         printf("\n");
19     }
20 }

# 2040  亲和数

 1 #include <stdio.h>
2
3 int qhs(int a){
4     int i,j,sum,s[50];
5     s[0]=1;j=1;
6     for(i=2;i<=a/2;i++){
7         if(a%i==0){s[j]=i;j++;}
8     }
9     sum=0;
10     for(i=0;i<j;i++){sum += s[i];}
11     return sum;
12 }
13
14 int main(){
15     int n,i,a,b,c,s[100];
16     while(scanf("%d",&n)!=EOF){
17         while(n--){
18             scanf("%d %d",&a,&b);
19             if(qhs(a)==b || qhs(b)==a){printf("YES\n");}
20             else{printf("NO\n");}
21         }
22     }
23 }

# 2042  不容易系列之二

 1 #include <stdio.h>
2
3 int main(){
4     int n,m,i;
5     while(scanf("%d",&n)!=EOF){
6         while(n--){
7             scanf("%d",&m);
8             i = 3;
9             while(m--){i = (i-1)*2;}
10             printf("%d\n",i);
11         }
12
13     }
14 }

# 2054  A == B ?

#include<stdio.h>
#include<string.h>
char a[100000],b[100000];
void change(char s[])
{
int len,i;
len=strlen(s);
if(strstr(s,"."))
{
for(i=len-1;s[i]=='0';i--)
{
s[i]='\0';
len--;
}
}
if(s[len-1]=='.')
s[len-1]='\0';
}
int main()
{
while(~scanf("%s %s",&a,&b))
{
change(a);
change(b);
if(strcmp(a,b)==0)
printf("YES\n");
else
printf("NO\n");
}
return 0;
}

# 2055  An easy problem

 1 #include <stdio.h>
2 #include <string.h>
3
4 int f(char a){
5     if(a>='A'&&a<='Z'){return a-64;}
6     if(a>='a'&&a<='z'){return 96-a;}
7 }
8
9 int main(){
10     char a;
11     int n,b,sum;
12     while(scanf("%d",&n)!=EOF){
13         getchar();
14         while(n--){
15
16             scanf("%c %d",&a,&b);
17             getchar();
18             sum = b + f(a);
19             printf("%d\n",sum);
20
21         }
22     }
23 }

posted @ 2019-02-25 21:45  Ragd0ll  阅读(323)  评论(0编辑  收藏