摘要：
1. 有字符串 "k:1|k1:2|k2:3|k3:4" 处理成字典 {"k":1, "k1":2,...} a1 = "k:1|k1:2|k2:3|k3:4" a2 = a1.split("|") # ['k:1', 'k1:2', 'k2:3', 'k3:4'] lis = {} for a3 阅读全文
posted @ 2019-04-28 22:01 S-skill 阅读(154) 评论(0) 推荐(0)
posted @ 2019-04-28 22:01 S-skill 阅读(154) 评论(0) 推荐(0)
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