摘要: #include "stdafx.h"#include<stdio.h>int main(){ long i,s=0;for(i=22;i<=1002;i=i+20)s=s+i; printf("%d\n",s); return 0;} #include "stdafx.h"#include<std 阅读全文
posted @ 2019-05-09 15:30 Lansen 阅读(78) 评论(0) 推荐(0)