摘要:
int add(int x,int y) {int a; a=x+y; return a; } int minus(int x,int y) {int mi; mi=x-y; return mi; } int multip(int x,int y) {int mu; mu=x*y; return m 阅读全文
posted @ 2019-06-06 13:56
201821430014
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