task1

源码:

#include<stdio.h>
#define N 4
void test1(){
	int a[N] = {1,9,8,4};
	int i;
	printf("sizeof(a) = %d\n",sizeof(a));
	for (i = 0;i<N;++i)
	     printf("%p:%d\n",&a[i],a[i]);
	printf("a = %p\n",a);
}
void test2(){
	char b[N] ={'1','9','8','4'};
	int i;
	printf("sizeof(b) = %d\n",sizeof(b));
	for (i = 0;i < N;++i)
	     printf("%p:%c\n",&b[i],b[i]);
	printf("b = %p\n",b); 
}
int main(){
	printf("测试1:int类型一维数组\n");
	test1();
	printf("\n测试2:char类型一维数组\n");
	test2();
	return 0;
} 

  

#include<stdio.h>
#define N 2
#define M 4
void test1(){
	int a[N][M] = {{1,9,8,4},{2,0,4,9}};
	int i,j;
	printf("sizeof(a) = %d\n",sizeof(a));
	for (i = 0;i < N;++i)
	    for(j = 0;j < M;++j)
	        printf("%p:%d\n",&a[i][j],a[i][j]);
    printf("\n");
    printf("a = %p\n",a);
    printf("a[0] = %p\n",a[0]);
    printf("a[1] = %p\n",a[1]);
    printf("\n");
} 
void test2(){
	char b[N][M] = {{'1','9','8','4'},{'2','0','4','9'}};
	int i,j;
	printf("sizeof(b) = %d\n",sizeof(b));
	for(i = 0;i < N;++i)
	    for(j = 0;j < M;++j)
	        printf("%p:%c\n",&b[i][j],b[i][j]);
	printf("\n");
	printf("b = %p\n",b);
	printf("b[0] = %p\n",b[0]);
	printf("b[1] = %p\n",b[1]);
}
int main(){
	printf("测试1:int类型两维数组");
	test1();
	printf("测试2:char类型两维数组");
	test2();
	return 0;
}

截图:

task2

源码:

#include<stdio.h>
#include<string.h>
#define N 80
void swap_str(char s1[N], char s2[N]);
void test1();
void test2();
int main(){
	printf("测试1:用两个一维char数组,实现两个字符串交换\n");
	test1();
	printf("测试2:用二维char数组,实现两个字符串交换\n");
	test2();
	return 0;
}
void test1(){
	char views1[N] = "hey, C, I hate u.";
	char views2[N] = "hey, C, I love u.";
	printf("交换前:\n");
	puts(views1);
	puts(views2);
	swap_str(views1,views2);
	printf("交换后:\n");
	puts(views1);
	puts(views2);
}

void test2(){
	char views[2][N] = {"hey,C,I hate u.",
	                    "hey,C,I love u."};
	printf("交换前:\n");
	puts(views[0]);
	puts(views[1]);
	swap_str(views[0],views[1]);
	printf("交换后:\n");
	puts(views[0]);
	puts(views[1]);
}

void swap_str(char s1[N], char s2[N]){
	char tmp[N];
	strcpy(tmp,s1);
	strcpy(s1,s2);
	strcpy(s2,tmp);
}

截图:

task3

源码:

#include<stdio.h>
#define N 80
int count(char x[]);
int main(){
	char words[N+1];
	int n;
	while(gets(words)!=NULL){
		n = count(words);
		printf("单词数:%d\n\n",n);
	}
	return 0;
}

int count(char x[]){
	int i;
	int word_flag = 0;
	int number = 0;
	for(i = 0;x[i]!='\0';i++){
		if(x[i] == ' ')
		   word_flag = 0;
		else if(word_flag == 0){
			word_flag = 1;
			number++;
		}
	}
	return number;
}

  

#include <stdio.h>
#define N 1000

int main() {
    char line[N];
    int word_len;   
    int max_len;    
    int end;        
    int i;

    while(gets(line) != NULL) {
        word_len = 0;
        max_len = 0;
        end = 0;

        i = 0;
        while(1) {
            while(line[i] == ' ') {
                word_len = 0; 
                i++;
            }

            while(line[i] != '\0' && line[i] != ' ') {
              word_len++;
                 i++;
             }
        
             if(max_len < word_len) {
                 max_len = word_len;
                end = i;   
            } 
             if(line[i] == '\0')
                 break;
         }
 
         printf("最长单词: ");
         for(i = end - max_len; i < end; ++i)
             printf("%c", line[i]);
         printf("\n\n");
     }
 
    return 0;
}

截图:

 

task4

源码:

#include<stdio.h>
#define N 100
void dec_to_n(int x,int n);

int main(){
	int x;
	printf("输入一个十进制整数:");
	while(scanf("%d",&x)!=EOF){
		dec_to_n(x,2);
		dec_to_n(x,8);
		dec_to_n(x,16);
		printf("\n输入一个十进制整数:");
	}
	return 0;
}

void dec_to_n(int x,int n){
	char map[] = {"0123456789ABCDEF"};
	char ans[N];
	int r,i;
	int cnt = 0;
	
	do{
		r = x % n;
		ans[cnt] = map[r];
		cnt++;
		x = x/n;
	}   while(x!=0);
		for(i = cnt - 1;i>=0;--i){
			 printf("%c",ans[i]);
		}
	printf("\n");
}

截图:

task5

源码:

#include<stdio.h>
#define N 5

void input(int x[],int n);
void output(int x[],int n);
double average(int x[],int n);
void bubble_sort(int x[],int n);

int main(){
	int scores[N];
	double ave;
	
	printf("录入%d个分数:\n", N);
	input(scores, N);
	
	printf("\n输出课程分数:\n");
	output(scores, N);
	
	printf("\n课程分数处理:计算均分、排序...\n");
	ave = average(scores, N);
	bubble_sort(scores, N);
	
	printf("\n输出课程均分:%.2f\n",ave);
	printf("\n输出课程分数(高->低):\n");
	output(scores, N);
	
	return 0;
} 


void input(int x[],int n){
	int i;
	
	for(i = 0;i < n; ++i)
		scanf("%d",&x[i]);
}

void output(int x[],int n){
	int i;
	
	for(i = 0;i < n; ++i)
		printf("%d ",x[i]);
	printf("\n");
}


double average(int x[],int n){
	int i;
	double sum = 0.0,ave;
	
	for(i = 0;i<+n;i++)
	sum+=x[i];
	ave=sum/n;
	return ave;
}


void bubble_sort(int x[], int n){
     int i,j,temp,flag;
     for(i = 0;i < n-1;i++){
        flag = 0;
        for(j = 0;j < n-i-1;j++){
             if(x[j] < x[j+1]){
                 flag = 1;
                 temp = x[j];
                 x[j] = x[j+1];
                 x[j+1] = temp;
             }
         }
         if(flag == 0){
             break;
         }
     }
     for(i = 0;i < n;i++){
         printf("%d ",x[i]);
     }
     
 }

截图:

task6

源码:

#include <stdio.h>
#include <string.h> 
#define N 5
#define M 20

void output(char str[][M], int n);
void bubble_sort(char str[][M], int n);
int main() {
    char name[][M] = {"Bob", "Bill", "Joseph", "Taylor", "George"};
    int i;
 
    printf("输出初始名单:\n");
    output(name, N);
 
     printf("\n排序中...\n");
     bubble_sort(name, N);  
 
    printf("\n按字典序输出名单:\n");
     output(name, N);
 
     return 0;
 }
 
 
void output(char str[][M], int n) {
     int i;

     for(i = 0; i < n; ++i)
         printf("%s\n", str[i]);
 }
 

 void bubble_sort(char str[][M], int n){
     char temp[M];
     int i,j,flag;
     for(i = 0;i < n-i-1;i++){
         flag = 0;
         for(j = 0;j < n-i-1;j++){
             if(strcmp(str[j],str[j+1]) > 0){
                 flag = 1;
                 strcpy(temp,str[j]);
                 strcpy(str[j],str[j+1]);
                 strcpy(str[j+1],temp);
            }
         }
         if(flag == 0){
            break;
         }
     }
 }

截图:

task7

源码:

#include<stdio.h>
#include<string.h>
int main(){
     char A[100];
     char a;
     int i,j,num,len,flag;
     while(scanf("%s",&A) != EOF){
        len = strlen(A);
         flag = 0;
         for(i = 0;i < len;i++){
             a = A[i];
             num = 0;
             for(j = 0;j < len;j++){
                 if(a == A[j]){
                     num++;
                 }
             }
             if(num > 1){
                 printf("Yes\n");
                 flag = 1;
                 break;
             }
         }
         if(flag == 0){
            printf("No\n");
         }
         
     }  
     return 0;
	  }

截图:

task8

源码:

#include<stdio.h>
#include<stdlib.h>
#define N 100
#define M 4
void output(int x[][N], int n);          
void rotate_to_right(int x[][N], int n); 
int main() {
     int t[][N] = {{21, 12, 13, 24},
                   {25, 16, 47, 38},
                   {29, 11, 32, 54},
                   {42, 21, 33, 10}};
     printf("原始矩阵:\n");
     output(t, M);
     rotate_to_right(t, M);
     printf("变换后矩阵:\n");
     output(t, M);
     system("pause");
     return 0;
 }

void output(int x[][N], int n) {
    int i, j;
     for (i = 0; i < n; ++i) {
         for (j = 0; j < n; ++j)
             printf("%4d", x[i][j]);
         printf("\n");
     }
 }

void rotate_to_right(int x[][N], int n)
{
     int y[N][N];
     for(int i=0;i<n;i++)
         for(int j=0;j<n;j++)
             y[i][j]=x[i][j];
     for(int i=n-1;i>0;i--)
     {
         for(int j=0;j<n;j++)
             x[j][i]=y[j][i-1];
     }
     for(int j=0;j<n;j++)
	             x[j][0]=y[j][n-1];
 }

截图:

 

posted on 2023-11-19 23:18  神里凌华  阅读(9)  评论(0编辑  收藏  举报