摘要: int xx(point a) //判断象限 { if(a.x>0&&a.y>=0)return 1; if(a.x<=0&&a.y>0)return 2; if(a.x<0&&a.y<=0)return 3; if(a.x>=0&&a.y<0)return 4; } double cj(node 阅读全文
posted @ 2019-10-08 16:02 Mmasker 阅读(222) 评论(0) 推荐(0)