摘要：
name = ['David','Eva','Tony'] #list print(name[1]) scores = [105,68,70] #list d = {'David':105,'Eva':68,'Tony':70} #dict d['Eva']=88 d['Tony']=78 d.pop('David') print(d) att = {'name': '20170909... 阅读全文
posted @ 2018-06-06 21:41
王明哲0
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