摘要:
"传送门" Solution 设dp方程dp[now][pos][red][fla]表示还有now个位置,pos表示匹配到第几位,red表示左括号数 右括号数,fla表示是否已经是给定串的字串 暴力转移即可 Code 优美的记搜: cpp include include include includ 阅读全文
摘要:
"传送门" Solution 一道比较好的dp题 想了半天组合数QAQ 首先要知道的是 A include include include include define F(i,a,b) for(register int i=(a);i n m; for(int i=0;(1 i)&1,c=j&1; 阅读全文
摘要:
"传送门" Description 给n(n include include include include define F(i,a,b) for(register int i=(a);ians) continue; // printf("%d %d %d %d %d\n",x,l[i],r[i] 阅读全文