Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given 1->2->3->4
, you should return the list as 2->1->4->3
.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.
思路:
递归。要搞清楚怎么交换,保证不被更新掉,画张图。1.next=2.next; 2.next=1.next 1.next=swap(1.next)
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public ListNode swapPairs(ListNode head) { if(head==null||head.next==null){ return head; } ListNode res=head.next; head.next=res.next; res.next=head; head.next=swapPairs(head.next); return res; } }