linux命令之grep:过滤注释行和空白行
摘要:
cat elasticsearch.yml | grep "^\s*[^# \t].*$" cat elasticsearch.yml | grep -v ^# |grep -v ^$ 阅读全文
posted @ 2018-04-27 14:28 Louiszj 阅读(7088) 评论(0) 推荐(1)
posted @ 2018-04-27 14:28 Louiszj 阅读(7088) 评论(0) 推荐(1)
posted @ 2018-04-27 14:26 Louiszj 阅读(653) 评论(0) 推荐(0)