ODT （Old Driver Tree）珂朵莉树 

  1 #include <bits/stdc++.h>
  2 using namespace std;
  3 
  4 typedef long long LL;
  5 const int MOD7 = 1e9 + 7;
  6 const int MOD9 = 1e9 + 9;
  7 const int imax_n = 1e5 + 7;
  8 LL add(LL a, LL b, LL mod)
  9 {
 10     LL res = 0;
 11     LL ans = a;
 12     while (b)
 13     {
 14         if (b&1) res = (res + ans) % mod;
 15         ans = (ans + ans) % mod;
 16         b>>=1;
 17     }
 18     return res;
 19 }
 20 
 21 LL pow(LL a, LL b, LL mod)
 22 {
 23     LL res = 1;
 24     LL ans = a % mod;
 25     while (b)
 26     {
 27         if (b&1) res = res * ans % mod;
 28         ans = ans * ans % mod;
 29         b>>=1;
 30     }
 31     return res;
 32 }
 33 
 34 struct node {
 35     int l,r;
 36     mutable LL v;
 37     node(int L, int R=-1, LL V=0):l(L), r(R), v(V){}
 38     bool operator<(const node& o) const {
 39         return l < o.l;
 40     }
 41 };
 42 
 43 set<node> s;
 44 
 45 set<node>::iterator split(int pos)
 46 {
 47     auto it = s.lower_bound(node(pos));
 48     if (it != s.end() && it->l == pos) return it;
 49     --it;
 50     if (pos > it->r) return s.end();
 51     int L = it->l, R = it->r;
 52     LL V = it->v;
 53     s.erase(it);
 54     s.insert(node(L, pos-1, V));
 55     return s.insert(node(pos, R, V)).first;
 56     // pair<iterator, bool> insert(const value_type& val);
 57 }
 58 
 59 void add(int l, int r, LL val=1)
 60 {
 61     split(l);
 62     auto itr = split(r+1), itl = split(l);
 63     for (; itl != itr; ++itl) itl->v += val;
 64 }
 65 
 66 void assign_val(int l, int r, LL val=0)
 67 {
 68     split(l);
 69     auto itr = split(r+1), itl = split(l);
 70     s.erase(itl, itr);
 71     s.insert(node(l, r, val));
 72 }
 73 
 74 LL rank_(int l, int r, int k, bool reversed=0)
 75 {
 76     vector<pair<LL, int>> vp;
 77     if (reversed) k = r - l + 2 - k;
 78     split(l);
 79     auto itr = split(r+1), itl = split(l);
 80     vp.clear();
 81     for (; itl != itr; ++itl)
 82         vp.push_back({itl->v, itl->r - itl->l + 1});
 83     sort(vp.begin(), vp.end());
 84     for (auto i: vp)
 85     {
 86         k -= i.second;
 87         if (k <= 0) return i.first;
 88     }
 89     return -1LL;
 90 }
 91 
 92 LL sum(int l, int r, int ex, int mod)
 93 {
 94     split(l);
 95     auto itr = split(r+1), itl = split(l);
 96     LL res = 0;
 97     for (; itl != itr; ++itl)
 98         res = (res + (LL)(itl->r - itl->l + 1) * pow(itl->v, LL(ex), LL(mod))) % mod;
 99     return res;
100 }
101 
102 int n, m;
103 LL seed, vmax;
104 
105 LL rnd()
106 {
107     LL ret = seed;
108     seed = (seed * 7 + 13) % MOD7;
109     return ret;
110 }
111 
112 LL a[imax_n];
113 
114 int main()
115 {
116     cin>>n>>m>>seed>>vmax;
117     for (int i=1;i<=n;++i)
118     {
119             a[i] = (rnd() % vmax) + 1;
120             s.insert(node(i,i,a[i]));
121     }
122     s.insert(node(n+1, n+1, 0));
123     int lines = 0;
124     for (int i =1; i <= m; ++i)
125     {
126         int op = int(rnd() % 4) + 1;
127         int l = int(rnd() % n) + 1;
128         int r = int(rnd() % n) + 1;
129         if (l > r)
130             swap(l,r);
131         int x, y;
132         // cout<<i<<"   op = "<<op<<"    ";
133         if (op == 3)
134             x = int(rnd() % (r-l+1)) + 1;
135         else
136             x = int(rnd() % vmax) +1;
137 
138         if (op == 4)
139             y = int(rnd() % vmax) + 1;
140         if (op == 1)
141             add(l, r, LL(x));
142         else if (op == 2)
143             assign_val(l, r, LL(x));
144         else if (op == 3)
145         {
146             // cout<<"lines"<<++lines<<endl;
147             cout<<rank_(l, r, x)<<endl;
148         }
149         else
150         {
151             // cout<<"lines"<<++lines<<endl;
152             cout<<sum(l, r, x, y)<<endl;
153         }
154     }
155     return 0;
156 }

 

posted @ 2018-07-13 08:26  LeeSongt  阅读(1100)  评论(0)    收藏  举报