task2
三.实验内容
1.实验任务1
tsak1.c
#include <stdio.h> #include <stdlib.h> #include <time.h> #define N 5 #define N1 80 #define N2 35 int main() { int cnt; int random_major, random_no; srand(time(NULL)); // 以当前系统时间作为随机种子 cnt = 0; while(cnt < N) { random_major = rand() % 2; if(random_major) { random_no = rand() % N1 + 1; printf("20256343%04d\n", random_no); } else { random_no = rand() % N2 + 1; printf("20256136%04d\n", random_no); } cnt++; } return 0; }
问题1:代码 srand(time(NULL));起使每次运行结果根据时间不同而变化的作用
问题2:功能为随机生成学号
2.实验任务2
task2.c
#include <stdio.h> int main() { int choice, quantity; float total_price = 0, amount_paid, change; while (1) { printf("\n自动饮料售卖机菜单:\n"); printf("1. 可乐 - 3 元/瓶\n"); printf("2. 雪碧 - 3 元/瓶\n"); printf("3. 橙汁 - 5 元/瓶\n"); printf("4. 矿泉水 - 2 元/瓶\n"); printf("0. 退出购买流程\n"); printf("请输入饮料编号: "); scanf("%d", &choice); if (choice == 0) break; if (choice < 1 || choice > 4) { printf("无效的饮料编号,请重新输入。\n"); continue; } printf("请输入购买的数量: "); scanf("%d", &quantity); if (quantity < 0) { printf("购买数量不能为负数,请重新输入。\n"); continue; } if(choice == 1 || choice == 2) total_price += 3 * quantity; else if(choice == 3) total_price += 5 * quantity; else total_price += 2 * quantity; printf("请投入金额: "); scanf("%f", &amount_paid); change = amount_paid - total_price; printf("本次购买总价: %.2f 元\n", total_price); printf("找零: %.2f 元\n", change); total_price = 0; } printf("感谢您的购买,欢迎下次光临!\n"); return 0; }
问题1:去掉这行代码后,total_price
变量不会在每次交易结束后再变回0
问题2:第一处是输入无效的饮料编号时,跳过本次循环。第二处是输入负数的购买数量时,跳过本次循环。
3.实验任务3
task3.c
#include <stdio.h>
int main() {
char ch;
while (scanf("%c",&ch)!=EOF)
{
if(ch=='y'){
printf("wait a minute\n");}
else if(ch=='g'){
printf("go go go\n");}
else if(ch=='r'){
printf("stop!\n");}
else {
printf("something must be wrong...\n");}
}
return 0; }
4.实验任务4
task4.c
1 #include <stdio.h> 2 int main() { 3 float expense; 4 float total = 0.0f; 5 float max = 0.0f; 6 float min = 20000.0f; 7 printf("输入今日开销直到输入-1终止:\n"); 8 while (1) { 9 scanf("%f", &expense); 10 if (expense == -1.0f) { 11 break; 12 } 13 if (expense <= 0.0f || expense > 20000.0f) { 14 printf("(0 < 每笔消费 <= 20000):\n"); 15 continue; 16 } 17 total += expense; 18 if (expense > max) { 19 max = expense; 20 } 21 if (expense < min) { 22 min = expense; 23 } 24 } 25 printf("今日累计消费总额:%.1f\n", total); 26 printf("今日最高一笔开销:%.1f\n", max); 27 printf("今日最低一笔开销:%.1f\n", min); 28 return 0; 29 }
5. 实验任务5
task5.c
#include <stdio.h> int main() { int a, b, c; while (scanf("%d %d %d", &a, &b, &c) != EOF) { if (a <= 0 || b <= 0 || c <= 0 || a + b <= c || a + c <= b || b + c <= a) { printf("不能构成三角形\n"); continue; } if (a == b && b == c) { printf("等边三角形\n"); } else if (a == b || a == c || b == c) { printf("等腰三角形\n"); } else if (a * a + b * b == c * c || a * a + c * c == b * b || b * b + c * c == a * a) { printf("直角三角形\n"); } else { printf("普通三角形\n"); } } return 0; }
6. 实验任务6
task6.c
#include <stdio.h> #include <stdlib.h> #include <time.h> int main() { srand(time(0)); int lucky_day = rand() % 30 + 1; int guess; int count = 0; printf("猜猜2025年11月哪一天是你的lucky day\n"); printf("开始喽,你有三次机会,猜吧(1~30):"); while (count < 3) { scanf("%d", &guess); count++; if (guess == lucky_day) { printf("哇,猜中了:)\n"); return 0; } else if (guess < lucky_day) { printf("你猜的日期早了,你的lucky day还没到呢\n"); } else { printf("你猜的日期晚了,你的lucky day在前面哦\n"); } if (count < 3) { printf("再猜(1~30):"); } } printf("次数用光啦。偷偷告诉你,11月你的lucky day是%d号\n", lucky_day); return 0; }
四、实验结论
1. 实验任务1
#include <stdio.h> #include <stdlib.h> #include <time.h> #define N 5 #define N1 80 #define N2 35 int main() { int cnt; int random_major, random_no; srand(time(NULL)); // 以当前系统时间作为随机种子 cnt = 0; while(cnt < N) { random_major = rand() % 2; if(random_major) { random_no = rand() % N1 + 1; printf("20256343%04d\n", random_no); } else { random_no = rand() % N2 + 1; printf("20256136%04d\n", random_no); } cnt++; } return 0; }
问题1:代码 srand(time(NULL));起使每次运行结果根据时间不同而变化的作用
问题2:功能为随机生成学号
2. 实验任务2
#include <stdio.h> int main() { int choice, quantity; float total_price = 0, amount_paid, change; while (1) { printf("\n自动饮料售卖机菜单:\n"); printf("1. 可乐 - 3 元/瓶\n"); printf("2. 雪碧 - 3 元/瓶\n"); printf("3. 橙汁 - 5 元/瓶\n"); printf("4. 矿泉水 - 2 元/瓶\n"); printf("0. 退出购买流程\n"); printf("请输入饮料编号: "); scanf("%d", &choice); if (choice == 0) break; if (choice < 1 || choice > 4) { printf("无效的饮料编号,请重新输入。\n"); continue; } printf("请输入购买的数量: "); scanf("%d", &quantity); if (quantity < 0) { printf("购买数量不能为负数,请重新输入。\n"); continue; } if(choice == 1 || choice == 2) total_price += 3 * quantity; else if(choice == 3) total_price += 5 * quantity; else total_price += 2 * quantity; printf("请投入金额: "); scanf("%f", &amount_paid); change = amount_paid - total_price; printf("本次购买总价: %.2f 元\n", total_price); printf("找零: %.2f 元\n", change); total_price = 0; } printf("感谢您的购买,欢迎下次光临!\n"); return 0; }
问题1:去掉这行代码后,total_price
变量不会在每次交易结束后再变回0
问题2:第一处是输入无效的饮料编号时,跳过本次循环。第二处是输入负数的购买数量时,跳过本次循环。
3. 实验任务3
#include <stdio.h> int main() { char ch; while (scanf("%c",&ch)!=EOF) { if(ch=='y'){ printf("wait a minute\n");} else if(ch=='g'){ printf("go go go\n");} else if(ch=='r'){ printf("stop!\n");} else { printf("something must be wrong...\n");} } return 0; }
4. 实验任务4
1 #include <stdio.h> 2 int main() { 3 float expense; 4 float total = 0.0f; 5 float max = 0.0f; 6 float min = 20000.0f; 7 printf("输入今日开销直到输入-1终止:\n"); 8 while (1) { 9 scanf("%f", &expense); 10 if (expense == -1.0f) { 11 break; 12 } 13 if (expense <= 0.0f || expense > 20000.0f) { 14 printf("(0 < 每笔消费 <= 20000):\n"); 15 continue; 16 } 17 total += expense; 18 if (expense > max) { 19 max = expense; 20 } 21 if (expense < min) { 22 min = expense; 23 } 24 } 25 printf("今日累计消费总额:%.1f\n", total); 26 printf("今日最高一笔开销:%.1f\n", max); 27 printf("今日最低一笔开销:%.1f\n", min); 28 return 0; 29 }
5. 实验任务5
#include <stdio.h> int main() { int a, b, c; while (scanf("%d %d %d", &a, &b, &c) != EOF) { if (a <= 0 || b <= 0 || c <= 0 || a + b <= c || a + c <= b || b + c <= a) { printf("不能构成三角形\n"); continue; } if (a == b && b == c) { printf("等边三角形\n"); } else if (a == b || a == c || b == c) { printf("等腰三角形\n"); } else if (a * a + b * b == c * c || a * a + c * c == b * b || b * b + c * c == a * a) { printf("直角三角形\n"); } else { printf("普通三角形\n"); } } return 0; }
6. 实验任务6
#include <stdio.h> #include <stdlib.h> #include <time.h> int main() { srand(time(0)); int lucky_day = rand() % 30 + 1; int guess; int count = 0; printf("猜猜2025年11月哪一天是你的lucky day\n"); printf("开始喽,你有三次机会,猜吧(1~30):"); while (count < 3) { scanf("%d", &guess); count++; if (guess == lucky_day) { printf("哇,猜中了:)\n"); return 0; } else if (guess < lucky_day) { printf("你猜的日期早了,你的lucky day还没到呢\n"); } else { printf("你猜的日期晚了,你的lucky day在前面哦\n"); } if (count < 3) { printf("再猜(1~30):"); } } printf("次数用光啦。偷偷告诉你,11月你的lucky day是%d号\n", lucky_day); return 0; }