摘要:
#include<stdio.h> int main(){ int n,i; scanf("%d",&n); i=0; for(;n!=1;){ if(n%2==0){ n=n/2; i=i+1; } else{ n=n*3+1; i=i+1; } } printf("%d",i); return 阅读全文
posted @ 2022-11-05 22:34
printf("赖狒狒");
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