摘要: public class Solution{ public List<List<Integer>> levelOrder( TreeNode root){ List<List<Integer>> res= new ArrayList<>(); if(root==null) return res; d 阅读全文
posted @ 2022-07-22 07:17 flag! 阅读(26) 评论(0) 推荐(0)
摘要: 1.List<List<Integer>> res= new ArrayList<>(); 2. dfs if(target==0) res.add(new ArrayList<Integer>(subset); return; if(target>0) return ; for (int i=in 阅读全文
posted @ 2022-07-22 07:09 flag! 阅读(32) 评论(0) 推荐(0)
摘要: 1. boolean 2. Character.isLetterOrDigit 3. two pointers 4. i<=j. 5. Character.toUpperCase(s.charAt(i)); public boolean isPalindrome(String s) { if(s.i 阅读全文
posted @ 2022-07-22 04:57 flag! 阅读(25) 评论(0) 推荐(0)