HDOJ-2054

A == B ?

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 88211    Accepted Submission(s): 13922

Problem Description

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

 

 

Input

each test case contains two numbers A and B.

 

 

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

 

 

Sample Input

1 2 2 2 3 3 4 3

 

 

Sample Output

NO YES YES NO

 

 

本以为是一道水题，没想到处处坑点，被坑了一发。。

数组尽量开大一点，注意小数后无意义的0

AC代码：

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
    
const int MAX=100000;
char a[MAX]={0},b[MAX]={0};

int main(){

    while(scanf("%s %s",&a,&b)!=EOF){
        int i=0;
        if(strchr(a,'.')){//a中是否含小数点 
            for(i=strlen(a)-1;a[i]=='0';i--)
                a[i]='\0';//消掉末尾的0 
                if(a[i]='.')
                a[i]='\0';//消掉无意义的小数点 
        }
        if(strchr(b,'.')){
            for(i=strlen(b)-1;b[i]=='0';i--)
                b[i]='\0';    
                if(b[i]='.')
                 b[i]='\0';
        }
        printf(strcmp(a,b)?"NO\n":"YES\n");//strcmp函数当a，b相等时返回值为0 
    }
    return 0;
}