python 【requests【新】】

 1 def getHtml(url):
 2     try:
 3 
 4         r = requests.get(url,timeout=10)
 5 
 6         r.raise_for_status()  #如果返回的不是200,抛出错误
 7 
 8         r.encoding = r.apparent_encoding
 9 
10         return r.text
11 
12     except:
13 
14         return "异常错误"
15 
16 if __name__ == "__main__":
17 
18     url = "http://www.baidu.com"
19 
20     print(getHtml(url))
21     
模板

 

posted @ 2018-08-03 14:57  Justice-V  阅读(87)  评论(0)    收藏  举报