摘要：#include#includeusing namespace std;int a[2000005];int main(){ int n,m; while(scanf("%d",&n)!=EOF) { for(int i=0; i<n; i++) ... 阅读全文

摘要：#include#include#includeusing namespace std;int main(){ char a[20],b[20]; while(scanf("%s%s",a,b) != EOF) { int na=0; for(int i=0; a[i]!='\0'; i++) { if(a[i]>='0'&&a[i]='0'&&b[i]<='9') nb=nb*10+b[i]-'0'; else continue;... 阅读全文

摘要：#include#include#includeusing namespace std;int main(){ int p,t,g1,g2,g3,gj; while(scanf("%d %d %d %d %d %d",&p,&t,&g1,&g2,&g3,&gj)!=EOF) { if(abs(g1-g2)=t && abs(g3-g2)=t) { printf("%.1f\n",(g3+g1+0.0)/2); } else if(abs(g3-g1)<=t && a.. 阅读全文

摘要：http://ac.jobdu.com/problem.php?pid=1553/* 时针和分针位mod12，之和再mod6计算大角度， 时针和分针的位置关系分4种情况讨论 然后加上时针小角度的转动。*/#includeint main(){ int h,m; while(scanf("%d%*c%d",&h,&m)!=EOF) { int a=h%12,b=m%12; float k=(m+0.0)/2; float q=(a+0.0)/12-(m*11.0)/(60*12); if(q>0) { ... 阅读全文