实验三
task1
#include <stdio.h>
long long fac(int n);
int main()
{
int i, n;
printf("Enter n: ");
scanf_s("%d", &n);
for (i = 1; i <= n; ++i)
printf("%d! = %lld\n", i, fac(i));
return 0;
}
long long fac(int n)
{
static long long p = 1;
printf("p = %lld\n", p);
p = p * n;
return p;
}
#include <stdio.h> int func(int, int); int main() { int k = 4, m = 1, p1, p2; p1 = func(k, m); p2 = func(k, m); printf("%d,%d\n", p1, p2); return 0; } int func(int a, int b) { static int m = 0, i = 2; i += m + 1; m = i + a + b; return (m); }
task2
#include <stdio.h> void printSymbol(int n, char symbol); int main() { int n; char symbol; while( scanf("%d %c", &n, &symbol) != EOF ) { printSymbol(n, symbol); printf("\n"); } return 0; } void printSymbol(int n,char symbol) { int i=0; for(;i<n;i++){ printf("%c",symbol); } }
task3
#include <stdio.h> long long fun(int n); // 函数声明 int main() { int n; long long f; while (scanf("%d", &n) != EOF) { f = fun(n); printf("n = %d, f = %lld\n", n, f); } return 0; } long long fun(int a) { long long result; if(a==1) result=1; else result=(fun(a-1)+1)*2-1; return result; }
task4
#include <stdio.h> #include<math.h> int isprime(int a); int main() { int a, n; int k = 0; for (a = 101; a <= 200; a++) { n = isprime(a); if (n == 1) { printf("%d", a); printf(" "); k++; } } printf("\n101~200之间一共有%d个非素数", k); return 0; } int isprime(int a) { double m; int i; m = sqrt(a * 1.0); for (i = 2; i <= m; i++) { if (a % i == 0) break; } if (i > m && a > 1) return 0; else return 1; }
task5
#include <stdio.h> long fun(long s); int main() { long s, t; printf("Enter a number: "); while (scanf_s("%ld", &s) != EOF) { t = fun(s); printf("new number is: %ld\n\n", t); printf("Enter a number: "); } return 0; } long fun(long x) { long a, b = 1, c = 0; while (x > 0) { a = x % 10; if (a % 2 != 0) { c += a * b; b *= 10; } x /= 10; } return c; }
task6
#include <stdio.h>
double fun(int n);
double jc(int n);
int main() {
int n;
double s;
printf("Enter n(1~10): ");
while (scanf_s("%d", &n) != EOF)
{
s = fun(n);
printf("n = %d, s= %f\n\n", n, s);
printf("Enter n(1~10): ");
}
return 0;
}
double fun(int n)
{
int b, a = 1;
double sum = 0;
for (b = 1; b <= n;b++) {
sum += 1 / jc(b) * a;
a *= -1;
}
return sum;
}
double jc(int n) {
if (n == 1)
return 1;
else
return n * jc(n - 1);
}