I am a slow walker,but I never walk backwards. Abraham Lincoln

GeekZRF

07 2017 档案

HDU 5988.Coding Contest 最小费用最大流
摘要:Coding Contest Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1751 Accepted Submission(s): 374 P 阅读全文

posted @ 2017-07-30 21:16 GeekZRF 阅读(1249) 评论(0) 推荐(1)

POJ 3686.The Windy's 最小费用最大流
摘要:The Windy's Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 5477 Accepted: 2285 Description The Windy's is a world famous toy factory that 阅读全文

posted @ 2017-07-29 22:16 GeekZRF 阅读(182) 评论(0) 推荐(0)

POJ 3469.Dual Core CPU 最大流dinic算法模板
摘要:Dual Core CPU Time Limit: 15000MS Memory Limit: 131072K Total Submissions: 24830 Accepted: 10756 Case Time Limit: 5000MS Description As more and more 阅读全文

posted @ 2017-07-29 17:31 GeekZRF 阅读(259) 评论(0) 推荐(0)

POJ 2135.Farm Tour 消负圈法最小费用最大流
摘要:Evacuation Plan Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 4914 Accepted: 1284 Special Judge Description The City has a number of muni 阅读全文

posted @ 2017-07-29 11:03 GeekZRF 阅读(526) 评论(0) 推荐(0)

POJ 2135.Farm Tour 最小费用流
摘要:Farm Tour Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 17307 Accepted: 6687 Description When FJ's friends visit him on the farm, he like 阅读全文

posted @ 2017-07-28 21:51 GeekZRF 阅读(193) 评论(0) 推荐(0)

HDU 2255.奔小康赚大钱 最大权匹配
摘要:奔小康赚大钱 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 9828 Accepted Submission(s): 4328 Problem 阅读全文

posted @ 2017-07-28 17:29 GeekZRF 阅读(117) 评论(0) 推荐(0)

POJ 3281.Dining 最大流
摘要:Dining Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 18479 Accepted: 8243 Description Cows are such finicky eaters. Each cow has a prefer 阅读全文

posted @ 2017-07-27 18:30 GeekZRF 阅读(164) 评论(2) 推荐(0)

POJ 3041.Asteroids 最小顶点覆盖
摘要:Asteroids Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 22905 Accepted: 12421 Description Bessie wants to navigate her spaceship through 阅读全文

posted @ 2017-07-23 16:04 GeekZRF 阅读(195) 评论(0) 推荐(0)

HDU 2665.Kth number 区间第K小
摘要:Kth number Time Limit: 15000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11394 Accepted Submission(s): 3465 Pr 阅读全文

posted @ 2017-07-14 19:39 GeekZRF 阅读(219) 评论(0) 推荐(0)

POJ 2014.K-th Number 区间第k小 (归并树)
摘要:K-th Number Time Limit: 20000MS Memory Limit: 65536K Total Submissions: 57543 Accepted: 19893 Case Time Limit: 2000MS Description You are working for 阅读全文

posted @ 2017-07-11 21:38 GeekZRF 阅读(186) 评论(0) 推荐(0)

分桶法和平方分割
摘要:分桶法:把一排物品或者平面分成桶,每个桶分别维护自己内部的信息,已到达高效计算的目的的方法。 其中,平方分割是把排成一排的n个元素每√n个分在一个桶内进行维护的方法的统称。这样的方法可以使对区间的操作复杂度降至O(√n)。 以RMQ为例: 基于平方分割的RMQ 给定一个数列a1,a2,a3,a4,a 阅读全文

posted @ 2017-07-08 13:48 GeekZRF 阅读(409) 评论(0) 推荐(0)

基于稀疏表(Sparse Table)的RMQ(区间最值问题)
摘要:在RMQ的其他实现方法中,有一种叫做ST的算法比较常见。 【构建】 dp[i][j]表示的是从i起连续的2j个数xi,xi+1,xi+2,...xi+2j-1( 区间为[i,i+2j-1] )的最值。 状态转移方程dp[i][j]=max/min(dp[i][j-1], dp[i+2j-1][j-1 阅读全文

posted @ 2017-07-07 13:46 GeekZRF 阅读(180) 评论(0) 推荐(0)

n的m划分 整数拆分问题
摘要:n的m划分 将n划分成若干个不超过m的数(正整数)的和,问有几种划分情况。 现在根据n和m的关系,考虑下面几种情况: 综上的递推表达式为: 将n划分成不超过m个数(正整数)的和,问有几种情况。 dp[i][j]表示j的i划分。 考虑n的m划分,如果对于每一个i都有xi>0,那么{xi-1}就对应了n 阅读全文

posted @ 2017-07-06 20:46 GeekZRF 阅读(1001) 评论(0) 推荐(0)

POJ 3320.Jessica's Reading Problem 尺取法
摘要:Jessica's Reading Problem Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 12488 Accepted: 4255 Description Jessica's a very lovely girl woo 阅读全文

posted @ 2017-07-04 21:33 GeekZRF 阅读(157) 评论(0) 推荐(0)

POJ 3061.Subsequence 尺取法
摘要:Subsequence Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 14910 Accepted: 6301 Description A sequence of N positive integers (10 < N < 10 阅读全文

posted @ 2017-07-04 21:08 GeekZRF 阅读(150) 评论(0) 推荐(0)

HDU 3407.Zjnu Stadium 加权并查集
摘要:Zjnu Stadium Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3726 Accepted Submission(s): 1415 Pr 阅读全文

posted @ 2017-07-03 22:03 GeekZRF 阅读(219) 评论(0) 推荐(0)

HDU 3861.The King’s Problem 强联通分量+最小路径覆盖
摘要:The King’s Problem Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2947 Accepted Submission(s): 1 阅读全文

posted @ 2017-07-02 20:33 GeekZRF 阅读(198) 评论(0) 推荐(0)

导航