摘要:
#include using namespace std; int main() { int n; int a[100],dp[100]; cin>>n; for(int i=0;i>a[i]; } for(int i=0;idp[i]) dp[i]=dp[j]+1; } } i... 阅读全文
posted @ 2018-09-19 21:47
Somnus、M
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摘要:
奔小康赚大钱 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1836 Accepted Submission(s): 798 Problem D 阅读全文
posted @ 2018-09-19 20:52
Somnus、M
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