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摘要: <Style TargetType="{x:Type DatePickerTextBox}"> <Setter Property="Control.Template"> <Setter.Value> <ControlTemplate> <TextBox x:Name="PART_TextBox" Text="{Binding Path=SelectedDate, StringFormat='yyy 阅读全文
posted @ 2019-09-20 10:48 FredGrit 阅读(659) 评论(0) 推荐(0)
摘要: 1 <DataGridTemplateColumn Header="Binding"> 2 <DataGridTemplateColumn.CellTemplate> 3 <DataTemplate> 4 <Image x:Name="BindImg" Height="30" Width="30" Source="{Binding IsBindable,Converter={StaticResou 阅读全文
posted @ 2019-09-19 11:16 FredGrit 阅读(537) 评论(0) 推荐(0)
摘要: <Style x:Key="workButtonStyle" TargetType="{x:Type Button}"> <Style.Triggers> <Trigger Property="IsMouseOver" Value="False"> <Setter Property="FontSize" Value="20"/> </Trigger> <Trigger Property="IsMo 阅读全文
posted @ 2019-09-18 17:20 FredGrit 阅读(1004) 评论(0) 推荐(0)
摘要: <Window x:Class="WpfApp53.MainWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/exp 阅读全文
posted @ 2019-09-15 17:08 FredGrit 阅读(598) 评论(0) 推荐(0)
摘要: static void Main(string[] args) { int i = 0; Parallel.For(0, 100, (x) => { Console.WriteLine(i); i++; }); Console.WriteLine($"i is {i}"); Console.Read 阅读全文
posted @ 2019-09-15 12:24 FredGrit 阅读(271) 评论(0) 推荐(0)
摘要: <?xml version="1.0" encoding="utf-8"?><packages> <package id="Prism" version="5.0.0" targetFramework="net452" /> <package id="Prism.Composition" versi 阅读全文
posted @ 2019-09-11 17:36 FredGrit 阅读(480) 评论(0) 推荐(0)
摘要: Prism.Unity 中UnityBootStrapper已经不用了,可以继承PrismApplication 1.Install-package Prism.Unity -v 7.2.0.1367 2. 3. 阅读全文
posted @ 2019-09-09 17:59 FredGrit 阅读(871) 评论(0) 推荐(1)
摘要: DictionaryDictionary is generic type Dictionary<TKey,TValue>Dictionary class is a strong type < TKey,TValue > Hence, you must specify the data types f 阅读全文
posted @ 2019-09-08 18:01 FredGrit 阅读(319) 评论(0) 推荐(0)
摘要: 1.query all the store procedures in the specfied db; 2.create proc with while loop 阅读全文
posted @ 2019-09-08 15:31 FredGrit 阅读(205) 评论(0) 推荐(0)
摘要: SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE TABLE [dbo].[YearSalary]( [year] [int] NULL, [salary] [money] NULL ) ON [PRIMARY] GO select * from yearsalary; select 'year' as WorkYear,[2011], 阅读全文
posted @ 2019-09-08 15:16 FredGrit 阅读(330) 评论(0) 推荐(0)
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