摘要: 字符串处理:unix的ELF哈希函数unsigned int ELFHash(char* str){ unsigned int hash = 0; unsigned int x = 0; while (*str){ hash = (hash << 4) + (*str++); if ((x = hash & 0xF0000000L) != 0){ hash ^= (x >> 24); hash &= ~x; } } return (hash & 0x7FFFFFFF);} BK... 阅读全文
posted @ 2012-09-08 10:17 E_star 阅读(294) 评论(0) 推荐(0)